Hello, I was in a hurry at the time, when I replied. You could do one thing: extract sublist using: list4 <- list(mango, banana, pineapple) b1<-list() for(i in 1:3){ b1[[i]]<-list() b1[[i]]<-list4[[i]][1] } b1 b<-list() for(i in 1:3){ b[[i]]<-list() b[[i]]<-lapply(b1[[i]][[1]],FUN=function(x)x[which.max(x)]) }
b2<-data.frame(do.call(rbind,b)) row.names(b2)<-c("mango","banana","pineapple") b2 apply(b2,2, function(x) x[which.max(x)]) $coconut $coconut$banana [1] 18 I guess, this is much better than calling individual sublists. A.K. ______________________________________ If you reply to this email, your message will be added to the discussion below: http://r.789695.n4.nabble.com/apply-function-over-same-column-of-all-objects-in-a-list-tp4638681p4638907.html This email was sent by arun kirshna (via Nabble) To receive all replies by email, subscribe to this discussion: http://r.789695.n4.nabble.com/template/NamlServlet.jtp?macro=subscribe_by_code&node=4638681&code=ci1oZWxwQHItcHJvamVjdC5vcmd8NDYzODY4MXwtNzg0MjM1NTA4 [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.