Hello,
If I understand it now, can't you do this:
Individual cases:
list4<-list(mango[[1]],banana[[1]],pineapple[[1]])
b<-list()
for(i in 1:3){
b[[i]]<-list()
b[[i]]<-lapply(list4[[i]],FUN=function(x)x[which.max(x)])
}
b1<-data.frame(do.call(rbind,b))
row.names(b1)<-c("mango","banana","pineapple")
b1
coconut
mango 6
banana 18
pineapple 9
apply(b1,2, function(x) x[which.max(x)])
#$coconut
#$coconut$banana
#[1] 18
#This is what you asked for the result.
A.K.
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