Hello,
If I understand it now, can't you do this:
Individual cases:
list4<-list(mango[[1]],banana[[1]],pineapple[[1]])
b<-list()
for(i in 1:3){
b[[i]]<-list()
b[[i]]<-lapply(list4[[i]],FUN=function(x)x[which.max(x)])
}
b1<-data.frame(do.call(rbind,b))
row.names(b1)<-c("mango","banana","pineapple")
b1
coconut
mango 6
banana 18
pineapple 9
apply(b1,2, function(x) x[which.max(x)])
#$coconut
#$coconut$banana
#[1] 18
#This is what you asked for the result.
A.K.
______________________________________
If you reply to this email, your message will be added to the discussion below:
http://r.789695.n4.nabble.com/apply-function-over-same-column-of-all-objects-in-a-list-tp4638681p4638886.html
This email was sent by arun kirshna (via Nabble)
To receive all replies by email, subscribe to this discussion:
http://r.789695.n4.nabble.com/template/NamlServlet.jtp?macro=subscribe_by_code&node=4638681&code=ci1oZWxwQHItcHJvamVjdC5vcmd8NDYzODY4MXwtNzg0MjM1NTA4
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
