Hello,
To know why, just evaluate the condition, with 't1$' before 'version_1':
which(as.character(t1$version_1) %in% a) != 0
[1] TRUE TRUE
It allways evaluates to TRUE, therefore, subset() returns all rows.
See if this isn't simpler than both of your forms.
v2 <- subset(t1, version_1 %in% a)
v2
id version_1
1 1 100-1
2 2 100-2
The trick is to use %in% when doing multiple comparisons. With the
vector with length equal to the number of observations on the left hand
side.
Hope this helps,
Rui Barradas
Em 13-07-2012 12:12, Charles Stangor escreveu:
Why does the subset not work in the which() version below?
Thank you
v1 <- subset(t1,
version_1==as.character("100-1")
| version_1==as.character("100-2"))
a<-c("100-1", "100-2")
v1 <- subset(t1, which(a==as.character(version_1)) != 0)
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