Hello,
Try this:
Dcr<-lapply(1:5,function(x) rnorm(10,15))
names(Dcr)<- c("Dcre1","Dcre2","Dcre3","Dcre4","Dcre5")
#Works
regCred<-lm(Dcr[[1]]~Dcr[[2]]+Dcr[[3]])
summary(regCred)
#Works
regCred2<-lm(Dcre1~Dcre2+Dcre3,data=Dcr)
summary(regCred)
# Do not work
regCred3<-lm(Dcr[[1]][1:5]~Dcr[[4]][1:5]+Dcre5,data=Dcr)
Error in model.frame.default(formula = Dcr[[1]][1:5] ~ Dcr[[4]][1:5] + :
variable lengths differ (found for 'Dcre5')
#I guess this is what happened in your example, when different variable lengths
are used
#If you had used,
regCred3<-lm(Dcr[[1]][1:5]~Dcr[[4]][1:5]+Dcre5[1:5],data=Dcr)
summary(regCred3)
#it works
#this also works
regCred4<-lm(Dcre1[1:5]~Dcre2[1:5]+Dcre3[6:10],data=Dcr)
Or you could convert the list to dataframe
Dcr2<-data.frame(Dcre1=Dcr$Dcre1,Dcre2=Dcr$Dcre2,Dcre3=Dcr$Dcre3)
#testing whether list and dataframe converted results are same
#From dataframe
regCred5<-lm(Dcre1~Dcre2+Dcre3,data=Dcr2[1:5,])
> summary(regCred5)
Call:
lm(formula = Dcre1 ~ Dcre2 + Dcre3, data = Dcr2[1:5, ])
Residuals:
1 2 3 4 5
-0.01262 0.09888 0.07133 -0.08494 -0.07265
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 16.53707 0.99604 16.603 0.00361 **
Dcre2 -0.27890 0.04185 -6.665 0.02178 *
Dcre3 0.21874 0.04643 4.711 0.04222 *
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
#Same model using list
regCred6<-lm(Dcre1[1:5]~Dcre2[1:5]+Dcre3[1:5],data=Dcr)
> summary(regCred6)
Call:
lm(formula = Dcre1[1:5] ~ Dcre2[1:5] + Dcre3[1:5], data = Dcr)
Residuals:
1 2 3 4 5
-0.01262 0.09888 0.07133 -0.08494 -0.07265
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 16.53707 0.99604 16.603 0.00361 **
Dcre2[1:5] -0.27890 0.04185 -6.665 0.02178 *
Dcre3[1:5] 0.21874 0.04643 4.711 0.04222 *
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 0.1173 on 2 degrees of freedom
Multiple R-squared: 0.9739, Adjusted R-squared: 0.9478
F-statistic: 37.28 on 2 and 2 DF, p-value: 0.02612
The difference is in the names of the coefficients.
names(coef(regCred6))
[1] "(Intercept)" "Dcre2[1:5]" "Dcre3[1:5]"
which you can change by,
names(regCred6$coef)<-names(regCred5$coef)
regCred6$coef
(Intercept) Dcre2 Dcre3
16.5370694 -0.2788988 0.2187360
Though, it won't change the names of coefficients in the summary. I tried
several ways, but so far not successful. I think in that case, the easiest way
is to assign the subset to a new variable and run the analysis.
e.g.
Dcre1new<-Dcre1[1:5]
Hope this was helpful.
A.K.
----- Original Message -----
From: "Lekgatlhamang, lexi Setlhare" <lexisetlh...@yahoo.com>
To: "r-help@r-project.org" <r-help@r-project.org>
Cc:
Sent: Saturday, June 30, 2012 6:04 PM
Subject: [R] Adjusting length of series
Hi
I have a follow up question, relating to subsetting to list items. After using
the list and min(sapply()) method to adjust the length of the variables, I
specify a dynamic regression equation using the variables in the list. My list
looks like this:
Dcr<-
list(Dcre1=DCred1,Dcre2=DCred2,Dcre3=DCred3,Dbobc1=DBoBC1,Dbobc2=DBoBC2,Dbobc3=DBoBC3,...)
By specifying the list items with names, I thought I could end by referencing
them (or subsetting the list) as, eg., Dcr$Dcre1 and get DCred1, Dcr$Dbobc1 and
get DBoBC1, etc so that the explanatory variables of the equation can be easily
associated with their respective original names. This way, I would avoid
specifying the list as Dcr<-list(Dcr1, Dcr2, Dcr, 3..., Dcr15) and then
subsetting the list using Dcr[[1]][1:29], Dcr[[[2]][1:29], ..., Dcr[[15]][1:29]
because the list has many variables (15) and referencing the variables with
numbers makes them lose their original names.
When I specify the list as Dcr<- list(Dcr1, Dcr2, ..., Dcr15), then the
regression equation specified as:
# Regression
regCred<-
lm(Dcr[[1]][1:29]~Dcr[[2]][1:29]+Dcr[[3]][1:29]+Dcr[[4]][1:29]+Dcr[[5]][1:29]+Dcr[[6]][1:29]+...)
runs without problems - the results are shown here below:
Call:
lm(formula = Dcr[[1]][1:29] ~ Dcr[[2]][1:29] + Dcr[[3]][1:29] +
Dcr[[4]][1:29] + Dcr[[5]][1:29] + Dcr[[6]][1:29])
Residuals:
Min 1Q Median 3Q Max
-86.293 -33.586 -9.969 40.147 117.965
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 81.02064 13.28632 6.098 3.21e-06 ***
Dcr[[2]][1:29] -0.97407 0.11081 -8.791 8.20e-09 ***
Dcr[[3]][1:29] -0.27950 0.05899 -4.738 8.95e-05 ***
Dcr[[4]][1:29] -0.07961 0.04856 -1.639 0.115
Dcr[[5]][1:29] -0.07180 0.05515 -1.302 0.206
Dcr[[6]][1:29] -0.01562 0.02086 -0.749 0.462
But when I specify the list with names as shown above, then the equation does
not run - as shown by the following error message
> # Regression
> regCred<- lm(Dcr[[1]][1:29]~Dcr[[2]][1:29]+Dcr[[3]][1:29]+Dcr[[4]][1:29]+
+ Dcr[[5]][1:29]+Dcr$Dbobc3)
Error in model.frame.default(formula = Dcr[[1]][1:29] ~ Dcr[[2]][1:29] + :
variable lengths differ (found for 'Dcr$Dbobc3')
> Dcr[[5]][1:29]+Dcr$Dbobc3[1:29])
Error: unexpected ')' in "Dcr[[5]][1:29]+Dcr$Dbobc3[1:29])"
NB: In the equation with error message, only the last term is specified by
referencing its name (ie., Dcr$Dbobc3[1:29]. Also note that the error occurs
whether I append '[1:29]' to Dcr$Dbobc or not.
How do I resolve this?
Thanks. Lexi
NB: I tried typing the above in the same email Petr used to reply me, but the
email could not be delivered due to size problems
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and provide commented, minimal, self-contained, reproducible code.
