Hello,
I solved my problem with the uneven numbers of legend elements, which
should be put into more than one rows, in the following way:
I added another legend element which is empty ("") and is filled with
"white":
legend(0,-1.4,xjust=0,ncol=3,legend=c(colnames(dat)[-1],""),fill=c("navyblue","steelblue4","steelblue2","lightsteelblue3","lightsteelblue1","white"),bty="n",border="white",cex=1.2)
Not quite such a nice way, but it works, anyway.
Marion
2012/5/11 Marion Wenty <marion.we...@gmail.com>
> Hello,
>
> thank you very much for your answers. Using the command ncol worked in my
> special case, if I have got a legend with 4 elements, but with 5 it doesn't
> work. I am using two functions which I had created and checked what might
> be the difference, so that the second one doesn't work, but I couldn't find
> out what the problem is. So I am including the text of my .csv files and my
> functions:
>
>
> My .csv file "abb8a" looks like this:
>
> ;sehr gut;eher gut;eher nicht gut;nicht gut
> Kontakt mit der Schule;46;49;4;1
> Die richtige Wahl;32;58;8;2
>
>
> mw_g_4stap<-function(pfad="F:/04 Archiv/04 Programme/19
> R_Syntaxe/Grafiken_Funktionen",abb="abb8a")
> {
> setwd(pfad)
> postscript(file=paste(abb,".eps",sep=""))
> dat<-read.csv2(paste(abb,".csv",sep=""),header=T,check.names=F)
> dat1<-t(as.matrix(dat[,2:5],nrow=2))
> colnames(dat1)<-dat[,1]
> zehn<-seq(10,100,10)
> xmax<-max(dat1)
> ind<-min(which(zehn>=xmax))
> ticks<-seq(0,100,10)
> par(las=1)
> par(mar=c(5.9,4.5+0.3529412*(max(nchar(colnames(dat1)))-1),1,1))
>
> barplot(dat1,width=0.61,horiz=T,col=c("steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),border="NA",axes=F,beside=F,xlim=c(0,100),cex.names=1.2,ylim=c(0,10))
> par(xpd=TRUE)
> abline(v = seq(10, 100, by = 10), col = "white")
> par(xpd=F)
> axis(1,at=ticks,las=1,labels=paste(ticks,"%",sep=""))
> par(xpd=TRUE)
>
> legend(0,-1.4,xjust=0,ncol=2,legend=colnames(dat)[-1],fill=c("steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),bty="n",border="white",cex=1.2)
> par(xpd=FALSE)
> dev.off()
> }
> mw_g_4stap()
>
> ###
>
> My .csv file "probe8_5" looks like this:
>
> ;stimme zu;stimme zu;stimme zu;stimme zu;stimme zu
> Eltern konnten mir beim ler;23;70;1;1;5
> leichte Ent;20;10;10;10;50
> leichte Ent;20;10;10;10;50
> leichte Ent;20;10;10;10;50
> leichte Ent;20;10;10;10;50
> leichte Ent;20;10;10;10;50
> leichte Ent;20;10;10;10;50
>
>
> mw_g_5stap<-function(pfad="F:/04 Archiv/04 Programme/19
> R_Syntaxe/Grafiken_Funktionen",abb="probe8_5")
> {
> setwd(pfad)
> postscript(file=paste(abb,".eps",sep=""))
> dat<-read.csv2(paste(abb,".csv",sep=""),header=T,check.names=F)
> dat1<-t(as.matrix(dat[,2:6],nrow=2))
> dat1
> colnames(dat1)<-dat[,1]
> dat1
> zehn<-seq(10,100,10)
> xmax<-max(dat1)
> ind<-min(which(zehn>=xmax))
> ticks<-seq(0,100,10)
> par(las=1)
> par(mar=c(5,4.5+0.3529412*(max(nchar(colnames(dat1)))-1),1,1))
>
> barplot(dat1,width=0.61,horiz=T,col=c("navyblue","steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),border="NA",axes=F,beside=F,xlim=c(0,100),cex.names=1.2,ylim=c(0,10))
> par(xpd=TRUE)
> abline(v = seq(10, 100, by = 10), col = "white")
> par(xpd=F)
> axis(1,at=ticks,las=1,labels=paste(ticks,"%",sep=""))
> par(xpd=TRUE)
>
> legend(0,-1.4,xjust=0,ncol=3,legend=colnames(dat)[-1],fill=c("navyblue","steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),bty="n",border="white",cex=1.2)
> dev.off()
> }
> mw_g_5stap()
>
> ###
>
> The first function works but the second one doesn't.
>
> Does anyone know why?
>
> Thank you very much for your help in advance!!
>
> Marion
>
>
>
> 2012/5/9 Uwe Ligges <lig...@statistik.tu-dortmund.de>
>
>>
>>
>> On 09.05.2012 13:23, Marion Wenty wrote:
>>
>>> dear r-helpers,
>>>
>>> i have got another question:
>>>
>>> i am using the functions
>>>
>>> par(xpd=T)
>>> legend
>>>
>>> to create a legend below the x-axis. i used the parameter horiz=T.
>>>
>>> now i would like to put the elements of the legend in two rows:
>>>
>>> e.g. if my legend has got 5 elements, i would like 3 elements in one row
>>> and the last two elements in the next row.
>>>
>>> does anyone know how to do that?
>>>
>>
>> Example:
>>
>> bp <- barplot(1)
>> par(xpd = TRUE)
>> legend(bp, 0, xjust=0.5, legend=letters[1:5], lwd=1:5, ncol=3)
>>
>> Uwe Ligges
>>
>>
>> thank you very much for your help in advance!
>>>
>>> marion
>>>
>>> [[alternative HTML version deleted]]
>>>
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>>> PLEASE do read the posting guide http://www.R-project.org/**
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>>>
>>
>
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