Hello,
thank you very much for your answers. Using the command ncol worked in my
special case, if I have got a legend with 4 elements, but with 5 it doesn't
work. I am using two functions which I had created and checked what might
be the difference, so that the second one doesn't work, but I couldn't find
out what the problem is. So I am including the text of my .csv files and my
functions:
My .csv file "abb8a" looks like this:
;sehr gut;eher gut;eher nicht gut;nicht gut
Kontakt mit der Schule;46;49;4;1
Die richtige Wahl;32;58;8;2
mw_g_4stap<-function(pfad="F:/04 Archiv/04 Programme/19
R_Syntaxe/Grafiken_Funktionen",abb="abb8a")
{
setwd(pfad)
postscript(file=paste(abb,".eps",sep=""))
dat<-read.csv2(paste(abb,".csv",sep=""),header=T,check.names=F)
dat1<-t(as.matrix(dat[,2:5],nrow=2))
colnames(dat1)<-dat[,1]
zehn<-seq(10,100,10)
xmax<-max(dat1)
ind<-min(which(zehn>=xmax))
ticks<-seq(0,100,10)
par(las=1)
par(mar=c(5.9,4.5+0.3529412*(max(nchar(colnames(dat1)))-1),1,1))
barplot(dat1,width=0.61,horiz=T,col=c("steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),border="NA",axes=F,beside=F,xlim=c(0,100),cex.names=1.2,ylim=c(0,10))
par(xpd=TRUE)
abline(v = seq(10, 100, by = 10), col = "white")
par(xpd=F)
axis(1,at=ticks,las=1,labels=paste(ticks,"%",sep=""))
par(xpd=TRUE)
legend(0,-1.4,xjust=0,ncol=2,legend=colnames(dat)[-1],fill=c("steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),bty="n",border="white",cex=1.2)
par(xpd=FALSE)
dev.off()
}
mw_g_4stap()
###
My .csv file "probe8_5" looks like this:
;stimme zu;stimme zu;stimme zu;stimme zu;stimme zu
Eltern konnten mir beim ler;23;70;1;1;5
leichte Ent;20;10;10;10;50
leichte Ent;20;10;10;10;50
leichte Ent;20;10;10;10;50
leichte Ent;20;10;10;10;50
leichte Ent;20;10;10;10;50
leichte Ent;20;10;10;10;50
mw_g_5stap<-function(pfad="F:/04 Archiv/04 Programme/19
R_Syntaxe/Grafiken_Funktionen",abb="probe8_5")
{
setwd(pfad)
postscript(file=paste(abb,".eps",sep=""))
dat<-read.csv2(paste(abb,".csv",sep=""),header=T,check.names=F)
dat1<-t(as.matrix(dat[,2:6],nrow=2))
dat1
colnames(dat1)<-dat[,1]
dat1
zehn<-seq(10,100,10)
xmax<-max(dat1)
ind<-min(which(zehn>=xmax))
ticks<-seq(0,100,10)
par(las=1)
par(mar=c(5,4.5+0.3529412*(max(nchar(colnames(dat1)))-1),1,1))
barplot(dat1,width=0.61,horiz=T,col=c("navyblue","steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),border="NA",axes=F,beside=F,xlim=c(0,100),cex.names=1.2,ylim=c(0,10))
par(xpd=TRUE)
abline(v = seq(10, 100, by = 10), col = "white")
par(xpd=F)
axis(1,at=ticks,las=1,labels=paste(ticks,"%",sep=""))
par(xpd=TRUE)
legend(0,-1.4,xjust=0,ncol=3,legend=colnames(dat)[-1],fill=c("navyblue","steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),bty="n",border="white",cex=1.2)
dev.off()
}
mw_g_5stap()
###
The first function works but the second one doesn't.
Does anyone know why?
Thank you very much for your help in advance!!
Marion
2012/5/9 Uwe Ligges <lig...@statistik.tu-dortmund.de>
>
>
> On 09.05.2012 13:23, Marion Wenty wrote:
>
>> dear r-helpers,
>>
>> i have got another question:
>>
>> i am using the functions
>>
>> par(xpd=T)
>> legend
>>
>> to create a legend below the x-axis. i used the parameter horiz=T.
>>
>> now i would like to put the elements of the legend in two rows:
>>
>> e.g. if my legend has got 5 elements, i would like 3 elements in one row
>> and the last two elements in the next row.
>>
>> does anyone know how to do that?
>>
>
> Example:
>
> bp <- barplot(1)
> par(xpd = TRUE)
> legend(bp, 0, xjust=0.5, legend=letters[1:5], lwd=1:5, ncol=3)
>
> Uwe Ligges
>
>
> thank you very much for your help in advance!
>>
>> marion
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________**________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/**listinfo/r-help<https://stat.ethz.ch/mailman/listinfo/r-help>
>> PLEASE do read the posting guide http://www.R-project.org/**
>> posting-guide.html <http://www.R-project.org/posting-guide.html>
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
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