Well I'd suggest learning to use the return key. It really helps improve the
readability of a posting.
Three of the for files came through okay but table3a has a problem. It looks
like some kind of extraneous charater(s) got into it but a second or so of
editing makes it work so we have all 4 tables now.
John Kane
Kingston ON Canada
> -----Original Message-----
> From: kristi.glo...@hotmail.com
> Sent: Thu, 10 May 2012 14:36:51 -0300
> To: r-help@r-project.org
> Subject: Re: [R] FW: averaging two tables (rows with columns)
>
>
> oppps, Now I used 'dput' function. Again I am sending. I am so sorry for
> inconvenience.
> HI R userI am sorry that my data was not readable formate in the last
> email. Agin I am trying to send it. hope this time, that table can be
> readable.As I mentioned earlier that I was struggling to figure out on
> how I can calculate the average from the two tables in R. Any one can
> help me? really your helpwould be grateful- I am spending so much time to
> figure it out. It should not be so hard, I think.I have very big data but
> I have created a hypothetical data for simplification.for exampleI have :
> table 1Table 1: species occurrence data> dput(table1)structure(list(X =
> structure(1:4, .Label = c("Plot1", "Plot2", "plot3", "plot4"), class =
> "factor"), speciesX = c(1L, 0L, 1L, 0L), speciesY = c(0L, 1L, 0L, 0L),
> speciesZ = c(1L, 1L, 0L, 1L), speciesXX = c(0L, 0L, 1L, 0L)), .Names =
> c("X", "speciesX", "speciesY", "speciesZ", "speciesXX"), class =
> "data.frame", row.names = c(NA, -4L))
> Table 2: table 2. species tolerance data> dput(table2)structure(list(X =
> structure(c(1L, 3L, 2L), .Label = c("SpeciesX", "SpeciesXY", "SpeciesY"),
> class = "factor"), EnviA = c(0.21, 0.1, 0.14), EnviB = c(0.4, 0.15,
> 0.16), EnviC = c(0.17, 0.18, 0.19)), .Names = c("X", "EnviA", "EnviB",
> "EnviC"), class = "data.frame", row.names = c(NA, -3L))> You may noticed
> that table 2 does not have species Z which was in tableTable 3: Now I
> want to get the average value of species tolerance in each plot based on
> each environmental value (EnviA or EnviB etc).The example of the out come
> (final table I was looking for it).Results table 3a: averages species
> tolerance in each plot based on EnviAsuch as: >
> dput(table3a)structure(list(X = structure(1:4, .Label = c("plot1",
> "plot2", "plot3", "plot4"), class = "factor"), speciesX = c(0.21, NA, NA,
> 0.21), speciesY = c(NA, 0.1, NA, NA), speciesZ = structure(c(1L, 1L, 1L,
> 1L), .Label = "Nodata", class = "factor"), speciesXX = c(0.14, NA, 0.14,
> NA), av!
> erage = c(0.175, 0.1, 0.14, 0.21)), .Names = c("X", "speciesX",
> "speciesY", "speciesZ", "speciesXX", "average"), class = "data.frame",
> row.names = c(NA, -4L))
> Table 3b
> Result table 3b: average species tolerance in plot based on EnviB>
> dput(table3b) structure(list(X = structure(1:4, .Label = c("plot1",
> "plot2", "plot3", "plot4"), class = "factor"), speciesX = c(0.4, NA, NA,
> 0.4), speciesY = c(NA, 0.15, NA, NA), speciesZ = structure(c(1L, 1L, 1L,
> 1L), .Label = "Nodata", class = "factor"), speciesXX = c(0.16, NA, 0.16,
> NA), average = c(0.28, 0.15, 0.16, 0.4)), .Names = c("X", "speciesX",
> "speciesY", "speciesZ", "speciesXX", "average"), class = "data.frame",
> row.names = c(NA, -4L))I hope this time the data would be readable
> formate. Would any one help me how I can calculate these?ThanksKristi
> Golver==
>
>
> again
>
>
> [[alternative HTML version deleted]]
>
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