oppps, Now I used 'dput' function. Again I am sending. I am so sorry for
inconvenience.
HI R userI am sorry that my data was not readable formate in the last email.
Agin I am trying to send it. hope this time, that table can be readable.As I
mentioned earlier that I was struggling to figure out on how I can calculate
the average from the two tables in R. Any one can help me? really your
helpwould be grateful- I am spending so much time to figure it out. It should
not be so hard, I think.I have very big data but I have created a hypothetical
data for simplification.for exampleI have : table 1Table 1: species occurrence
data> dput(table1)structure(list(X = structure(1:4, .Label = c("Plot1",
"Plot2", "plot3", "plot4"), class = "factor"), speciesX = c(1L, 0L, 1L, 0L),
speciesY = c(0L, 1L, 0L, 0L), speciesZ = c(1L, 1L, 0L, 1L), speciesXX = c(0L,
0L, 1L, 0L)), .Names = c("X", "speciesX", "speciesY", "speciesZ", "speciesXX"),
class = "data.frame", row.names = c(NA, -4L))
Table 2: table 2. species tolerance data> dput(table2)structure(list(X =
structure(c(1L, 3L, 2L), .Label = c("SpeciesX", "SpeciesXY", "SpeciesY"), class
= "factor"), EnviA = c(0.21, 0.1, 0.14), EnviB = c(0.4, 0.15, 0.16), EnviC =
c(0.17, 0.18, 0.19)), .Names = c("X", "EnviA", "EnviB", "EnviC"), class =
"data.frame", row.names = c(NA, -3L))> You may noticed that table 2 does not
have species Z which was in tableTable 3: Now I want to get the average value
of species tolerance in each plot based on each environmental value (EnviA or
EnviB etc).The example of the out come (final table I was looking for
it).Results table 3a: averages species tolerance in each plot based on
EnviAsuch as: > dput(table3a)structure(list(X = structure(1:4, .Label =
c("plot1", "plot2", "plot3", "plot4"), class = "factor"), speciesX = c(0.21,
NA, NA, 0.21), speciesY = c(NA, 0.1, NA, NA), speciesZ = structure(c(1L, 1L,
1L, 1L), .Label = "Nodata", class = "factor"), speciesXX = c(0.14, NA, 0.14,
NA), av!
erage = c(0.175, 0.1, 0.14, 0.21)), .Names = c("X", "speciesX", "speciesY",
"speciesZ", "speciesXX", "average"), class = "data.frame", row.names = c(NA,
-4L))
Table 3b
Result table 3b: average species tolerance in plot based on EnviB>
dput(table3b) structure(list(X = structure(1:4, .Label = c("plot1",
"plot2", "plot3", "plot4"), class = "factor"), speciesX = c(0.4, NA, NA, 0.4),
speciesY = c(NA, 0.15, NA, NA), speciesZ = structure(c(1L, 1L, 1L, 1L), .Label
= "Nodata", class = "factor"), speciesXX = c(0.16, NA, 0.16, NA), average =
c(0.28, 0.15, 0.16, 0.4)), .Names = c("X", "speciesX", "speciesY", "speciesZ",
"speciesXX", "average"), class = "data.frame", row.names = c(NA, -4L))I hope
this time the data would be readable formate. Would any one help me how I can
calculate these?ThanksKristi Golver==
again
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