This is correct , now working. I did not have the preceeding comma in "Data2[,i] . . ."
Thanks very much! Very much appreciated. Ben Neal -----Original Message----- From: Peter Ehlers [mailto:ehl...@ucalgary.ca] Sent: Thu 5/3/2012 3:04 PM To: Ben Neal Cc: Jim Lemon; r-help@r-project.org Subject: Re: [R] Simple plot loop Ben, I think that your original for-loop would work if you just replaced the 'i' in the lines() call with 'Data2[,i]': for (i in 2:length(Data2)) { lines(MONTH, Data2[, i], type="o", pch=22, lty=2, col="blue") } Peter Ehlers On 2012-05-03 07:04, Ben Neal wrote: > Jim, thanks for the reply. I tried what you recommend, but I still get an > error when running it, just as I did with the similar loops I was trying. > Here is the error: > > Error in xy.coords(x, y) : 'x' and 'y' lengths differ > > That comes from this code: > > #Get file > library(zoo) > setwd("/Users/benjaminneal/Documents/All Panama/1110_Panama/CNAT_Segmenting") > Data = read.csv("120503_CNAT_Summary.csv", header=T) > > #fill in missing data from last observation > Data2<- na.locf(Data) > attach(Data2) > > #Plot line, and make it loop > for(column in names(Data2)[2:length(Data2)]) > lines(MONTH,column,type="o",pch=22,lty=2,col="blue") > ------------------------------------------------ > The problem perhaps is in my data. My columns are observations over time, > column headers are individual names, and the first column is the time series > in months. An example is here: > MONTH Tag101 > 0 234 > 2 236 > 4 239 > 8 300 > 10 320 > > This then repeats for different individuals . . . I think my problem must be > that my length of MONTH is different than my length of observations of each > column . . . except that it is not, as far as I can tell! Thank you for > assisting me with this simple but frustrating problem - I have the greatest > respect for those of you who provide these answers that so many of us read > and utilize. Thank you. Ben Neal > > > -----Original Message----- > From: r-help-boun...@r-project.org on behalf of Jim Lemon > Sent: Thu 5/3/2012 3:40 AM > To: Ben Neal > Cc: r-help@r-project.org > Subject: Re: [R] Simple plot loop > > On 05/03/2012 05:50 PM, Ben Neal wrote: >> Trying to plot multiple lines from a simple matrix with headers (eight >> observations per column). I will be doing a number of these, with varying >> numbers of columns, and do not want to enter the header names for each one >> (I got frustrated and just wrote them out, which did work). >> >> Data reads fine, first plot is fine, but when i use the code at the bottom >> for a for i loop it tells me that x and y do not match. . . >> >> One other issue is that I would prefer not to specify the first column >> either, but when I enter Plot(MONTH, Data2[2] . . . it also does not plot. >> Should this not call the second column? >> >> Thank you very much for any comments. I know this is simple, but I >> appreciate any assistance. Cheers, Ben >> >> ######################################### >> >> # LOAD DATA FROM CSV >> library(zoo) >> setwd("/Users/benjaminneal/Documents/All Panama/1110_Panama/CNAT_Segmenting") >> Data = read.csv("120503_CNAT_Summary.csv", header=T) >> >> #fill in missing data from last observation >> Data2<- na.locf(Data) >> attach(Data2) >> >> # PLOT ALL ON ONE CHART >> plot(MONTH,T102, type="o", ann="False", ylim=c(1, 100), pch=22, lty=2, >> col="red") >> title(main="5m and 10 m Colpophylia natans colonies over time", ylab="% live >> coral / colony", >> xlab="Months", col.main="black", font.main=4) >> >> lines(MONTH,T162, type="o", pch=22, lty=2, col="red") >> lines(MONTH,T231, type="o", pch=22, lty=2, col="green") >> lines(MONTH,T250, type="o", pch=22, lty=2, col="green") >> >> ##(many other similar lines here, with entered column headers . . . up to 75) >> >> lines(MONTH,T373, type="o", pch=22, lty=2, col="blue") >> lines(MONTH,T374, type="o", pch=22, lty=2, col="blue") >> lines(MONTH,T377, type="o", pch=22, lty=2, col="blue") >> >> # Tried to add lines another way with for i loop, but this is the part not >> working >> for (i in 2:length(Data2)) { >> lines(MONTH, i, type="o", pch=22, lty=2, col="blue")) >> } >> ##################################### >> > Hi Ben, > I think what you may want in your loop is this: > > for(column in names(Data2)[2:length(Data2)]) > lines(MONTH,column,type="o",pch=22,lty=2,col="blue") > > But, if you want the first two lines to be green, you'll probably have > to get a vector of colors: > > colorvec<-rep("blue",length(Data2)) > colorvec[1]<-"red" > colorvec[2:3]<-"green" > > and change the above to: > > columnnames<-names(Data2) > for(column in 2:length(Data2)) > lines(MONTH,columnnames[column],type="o",pch=22,lty=2,col=colvec[column]) > > Jim > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
