Jim, thanks for the reply. I tried what you recommend, but I still get an error
when running it, just as I did with the similar loops I was trying. Here is the
error:
Error in xy.coords(x, y) : 'x' and 'y' lengths differ
That comes from this code:
#Get file
library(zoo)
setwd("/Users/benjaminneal/Documents/All Panama/1110_Panama/CNAT_Segmenting")
Data = read.csv("120503_CNAT_Summary.csv", header=T)
#fill in missing data from last observation
Data2 <- na.locf(Data)
attach(Data2)
#Plot line, and make it loop
for(column in names(Data2)[2:length(Data2)])
lines(MONTH,column,type="o",pch=22,lty=2,col="blue")
------------------------------------------------
The problem perhaps is in my data. My columns are observations over time,
column headers are individual names, and the first column is the time series in
months. An example is here:
MONTH Tag101
0 234
2 236
4 239
8 300
10 320
This then repeats for different individuals . . . I think my problem must be
that my length of MONTH is different than my length of observations of each
column . . . except that it is not, as far as I can tell! Thank you for
assisting me with this simple but frustrating problem - I have the greatest
respect for those of you who provide these answers that so many of us read and
utilize. Thank you. Ben Neal
-----Original Message-----
From: r-help-boun...@r-project.org on behalf of Jim Lemon
Sent: Thu 5/3/2012 3:40 AM
To: Ben Neal
Cc: r-help@r-project.org
Subject: Re: [R] Simple plot loop
On 05/03/2012 05:50 PM, Ben Neal wrote:
> Trying to plot multiple lines from a simple matrix with headers (eight
> observations per column). I will be doing a number of these, with varying
> numbers of columns, and do not want to enter the header names for each one (I
> got frustrated and just wrote them out, which did work).
>
> Data reads fine, first plot is fine, but when i use the code at the bottom
> for a for i loop it tells me that x and y do not match. . .
>
> One other issue is that I would prefer not to specify the first column
> either, but when I enter Plot(MONTH, Data2[2] . . . it also does not plot.
> Should this not call the second column?
>
> Thank you very much for any comments. I know this is simple, but I appreciate
> any assistance. Cheers, Ben
>
> #########################################
>
> # LOAD DATA FROM CSV
> library(zoo)
> setwd("/Users/benjaminneal/Documents/All Panama/1110_Panama/CNAT_Segmenting")
> Data = read.csv("120503_CNAT_Summary.csv", header=T)
>
> #fill in missing data from last observation
> Data2<- na.locf(Data)
> attach(Data2)
>
> # PLOT ALL ON ONE CHART
> plot(MONTH,T102, type="o", ann="False", ylim=c(1, 100), pch=22, lty=2,
> col="red")
> title(main="5m and 10 m Colpophylia natans colonies over time", ylab="% live
> coral / colony",
> xlab="Months", col.main="black", font.main=4)
>
> lines(MONTH,T162, type="o", pch=22, lty=2, col="red")
> lines(MONTH,T231, type="o", pch=22, lty=2, col="green")
> lines(MONTH,T250, type="o", pch=22, lty=2, col="green")
>
> ##(many other similar lines here, with entered column headers . . . up to 75)
>
> lines(MONTH,T373, type="o", pch=22, lty=2, col="blue")
> lines(MONTH,T374, type="o", pch=22, lty=2, col="blue")
> lines(MONTH,T377, type="o", pch=22, lty=2, col="blue")
>
> # Tried to add lines another way with for i loop, but this is the part not
> working
> for (i in 2:length(Data2)) {
> lines(MONTH, i, type="o", pch=22, lty=2, col="blue"))
> }
> #####################################
>
Hi Ben,
I think what you may want in your loop is this:
for(column in names(Data2)[2:length(Data2)])
lines(MONTH,column,type="o",pch=22,lty=2,col="blue")
But, if you want the first two lines to be green, you'll probably have
to get a vector of colors:
colorvec<-rep("blue",length(Data2))
colorvec[1]<-"red"
colorvec[2:3]<-"green"
and change the above to:
columnnames<-names(Data2)
for(column in 2:length(Data2))
lines(MONTH,columnnames[column],type="o",pch=22,lty=2,col=colvec[column])
Jim
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and provide commented, minimal, self-contained, reproducible code.
