Have a look at the Ryacas package which interfaces R to yacas. yacas can do exact arithmetic.
On Fri, Apr 4, 2008 at 11:43 AM, Rory Winston <[EMAIL PROTECTED]> wrote: > > Hi > > (If you're wondering, this is a Project Euler question :)) > > If I wanted to calculate the sum of the digits in the decimal representation > of 2^1000, what would be a good way to go about that? I've tried the > following methods: > > # Calculate the sum of digits in the decimal representation of 2^n > # Only works for smaller values of n > bsum <- function(n) { > s <- 0 > e <- floor(log10(2^n)) > for (i in seq(e,0,-1)) { > s <- s + (((2^n) %/% 10^i) %% 10) > } > s > } > > The above doesnt work, as I am using an integer modulus which has > insufficient precision. so I tried to coerce R to produce a full-precision > integer and sum the digits of that: > > bsum2 <- function(n) { > s <- 0 > strn <- formatC(2^n, format="fg") > sum(as.numeric(strsplit(strn,"")[[1]])) > } > > This also doesnt seem to work. Is there another way I can do this in R? > Cheers > Rory > -- > View this message in context: > http://www.nabble.com/Arbitrary-Precision-Numbers-tp16492549p16492549.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.