Hi
(If you're wondering, this is a Project Euler question :))
If I wanted to calculate the sum of the digits in the decimal representation
of 2^1000, what would be a good way to go about that? I've tried the
following methods:
# Calculate the sum of digits in the decimal representation of 2^n
# Only works for smaller values of n
bsum <- function(n) {
s <- 0
e <- floor(log10(2^n))
for (i in seq(e,0,-1)) {
s <- s + (((2^n) %/% 10^i) %% 10)
}
s
}
The above doesnt work, as I am using an integer modulus which has
insufficient precision. so I tried to coerce R to produce a full-precision
integer and sum the digits of that:
bsum2 <- function(n) {
s <- 0
strn <- formatC(2^n, format="fg")
sum(as.numeric(strsplit(strn,"")[[1]]))
}
This also doesnt seem to work. Is there another way I can do this in R?
Cheers
Rory
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