Sorry, I meant Do you know of a way to print a string such that I can see whether it contains a *space* or a no-break space?
On Fri, Feb 3, 2012 at 10:10 AM, G See <gsee...@gmail.com> wrote: > Petr, > > Thank you! That is great. > > Do you know of a way to print a string such that I can see whether it > contains a string or a no-break space? > > Thanks, > Garrett > > On Fri, Feb 3, 2012 at 10:01 AM, Petr Savicky <savi...@cs.cas.cz> wrote: >> On Fri, Feb 03, 2012 at 09:25:10AM -0600, G See wrote: >>> I have a data.frame named "df". The dput of df is at the bottom of this >>> e-mail. >>> What I'd like to do is replace the "n/a " values with NA. On Mac OSX, it >>> works >>> to do this: >>> df[df == "n/a"] <- NA >>> >>> However, it does not work on Ubuntu. See below. >>> >>> Thanks in advance, >>> Garrett >>> >>> > x <- df[27, 4] # complete data.frame dput is below >>> > dput(x) >>> "n/a " >> >> Hi. >> >> This string contains a no-break space, not a space. >> >> "n/a " == "n/a\uA0" >> >> [1] TRUE >> >> "n/a\uA0" >> >> [1] "n/a " >> >> Hope this helps. >> >> Petr Savicky. >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
