Petr, Thank you! That is great.
Do you know of a way to print a string such that I can see whether it contains a string or a no-break space? Thanks, Garrett On Fri, Feb 3, 2012 at 10:01 AM, Petr Savicky <savi...@cs.cas.cz> wrote: > On Fri, Feb 03, 2012 at 09:25:10AM -0600, G See wrote: >> I have a data.frame named "df". The dput of df is at the bottom of this >> e-mail. >> What I'd like to do is replace the "n/a " values with NA. On Mac OSX, it >> works >> to do this: >> df[df == "n/a"] <- NA >> >> However, it does not work on Ubuntu. See below. >> >> Thanks in advance, >> Garrett >> >> > x <- df[27, 4] # complete data.frame dput is below >> > dput(x) >> "n/a " > > Hi. > > This string contains a no-break space, not a space. > > "n/a " == "n/a\uA0" > > [1] TRUE > > "n/a\uA0" > > [1] "n/a " > > Hope this helps. > > Petr Savicky. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
