On Thu, May 5, 2011 at 6:28 PM, J <jonsle...@gmail.com> wrote: > Hi, I'm requesting you don't berate me for asking this question: > > I clearly don't have the gist of factors. > > I have two dataframes, A and B. > > Each of them has a column containing strings (they're labels). > > I want to, one-by-one in a loop, compare the particular string in an entry > from dataframe A to an entry in B, to see if they're the same. > > The problem, when posing the question: > searchID1 <- A[['label']][i] > possMatch1 <- B[['label']][j] > searchID1 == possMatch1 > > I get the error: > Error in Ops.factor(searchID1, possMatch1) : > level sets of factors are different > > I presume this is because the set of possible values in the 'labels' columns, > respectively in A and B, differ. In my case, I'm not interested in this at > all; I just want to compare individual entries from the two dataframes in a > pair-wise fashion. > > Can I strip the "factors" associated with the entries? Is there a better way? >
Assuming you read them in using read.table, use read.table(...whatever..., as.is = TRUE) and then it will read them as character strings rather than factors. -- Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
