Hi Jonathan, On Thu, May 5, 2011 at 6:28 PM, J <jonsle...@gmail.com> wrote: > Hi, I'm requesting you don't berate me for asking this question: > > I clearly don't have the gist of factors. > > I have two dataframes, A and B. > > Each of them has a column containing strings (they're labels). > > I want to, one-by-one in a loop, compare the particular string in an entry > from dataframe A to an entry in B, to see if they're the same.
This is probably not the best way. Much easier to compare them all in one go. > > The problem, when posing the question: > searchID1 <- A[['label']][i] > possMatch1 <- B[['label']][j] > searchID1 == possMatch1 > > I get the error: > Error in Ops.factor(searchID1, possMatch1) : > level sets of factors are different > > I presume this is because the set of possible values in the 'labels' columns, > respectively in A and B, differ. In my case, I'm not interested in this at > all; I just want to compare individual entries from the two dataframes in a > pair-wise fashion. > > Can I strip the "factors" associated with the entries? Is there a better way? Yes, you can "strip the factors" using as.character(). Alternatively, you could use set the factor levels using factor() or levels. Either way, I would just do A$label == B$label Instead of a loop. Best, Ista > > Jonathan > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Ista Zahn Graduate student University of Rochester Department of Clinical and Social Psychology http://yourpsyche.org ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
