Thank you very much list!
On Mon, Sep 13, 2010 at 5:04 PM, Phil Spector <spec...@stat.berkeley.edu>wrote:
> Sunny -
> I don't think mapply is needed:
>
> lapply(1:length(mylist),function(x)rep(x,length(mylist[[x]])))
>>
> [[1]]
> [1] 1 1 1
>
> [[2]]
> [1] 2
>
> [[3]]
> [1] 3 3
>
> - Phil Spector
> Statistical Computing Facility
> Department of Statistics
> UC Berkeley
> spec...@stat.berkeley.edu
>
>
>
> On Mon, 13 Sep 2010, Sunny Srivastava wrote:
>
> Dear R-Helpers,
>> I have a list l1 like:
>>
>> l1[[1]]
>> a b c
>>
>> l1[[2]]
>> d
>>
>> l1[[3]]
>> e f
>>
>> I want an output res like:
>>
>> res[[1]]
>> 1 1 1
>>
>> res[[2]]
>> 2
>>
>> res[[3]]
>> 3 3
>>
>> Essentially, I want to replicate each index equal to the number of
>> elements
>> present in that index.
>>
>> Below is what I do to accomplish this:
>>
>> l1 <- list(c("a", "b", "c"), "d", c("e", "f"))
>> res <- mapply(rep, seq_along(l1),times=(lapply(l1, length)))
>>
>> Is there a more elegant way of doing this (possibly using one (l/m)apply
>> function)?
>>
>> Thanks in advance for the help.
>>
>> Best Regards,
>> S.
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
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>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
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