Try this:
relist(rep(1:length(l1), sapply(l1, length)), l1)
On Mon, Sep 13, 2010 at 3:41 PM, Sunny Srivastava
<research.b...@gmail.com>wrote:
> Dear R-Helpers,
> I have a list l1 like:
>
> l1[[1]]
> a b c
>
> l1[[2]]
> d
>
> l1[[3]]
> e f
>
> I want an output res like:
>
> res[[1]]
> 1 1 1
>
> res[[2]]
> 2
>
> res[[3]]
> 3 3
>
> Essentially, I want to replicate each index equal to the number of elements
> present in that index.
>
> Below is what I do to accomplish this:
>
> l1 <- list(c("a", "b", "c"), "d", c("e", "f"))
> res <- mapply(rep, seq_along(l1),times=(lapply(l1, length)))
>
> Is there a more elegant way of doing this (possibly using one (l/m)apply
> function)?
>
> Thanks in advance for the help.
>
> Best Regards,
> S.
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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