Hi Duncan,

Thanks for your response.

Indeed, independent normal errors were what I had in mind. As for variances, if 
I assume they are the same, would a 'pooled model' apply in this case? Is that 
equivalent to your suggestion of concatenating x(1,t) and x(2,t)?

Cheers,
Murali 

-----Original Message-----
From: Duncan Murdoch [mailto:murdoch.dun...@gmail.com] 
Sent: 31 August 2010 12:31
To: Menon Murali
Cc: r-help@r-project.org
Subject: Re: [R] simultaneous estimation

On 31/08/2010 6:58 AM, murali.me...@avivainvestors.com wrote:
> Hi folks,
> 
> Not sure what this sort of estimation is called. I have a 2-column 
> time-series x(i,t) [with (i=1,2; t=1,...T)], and I want to do the following 
> 'simultaneous' regressions:
> 
> x(1,t) = (d - 1)(x(1, t-1) - mu(1))
> x(2,t) = (d - 1)(x(2, t-1) - mu(2))
> 
> And I want to determine the coefficients d, mu(1), mu(2). 
> 
> Note that the d should be the same for both estimations, whereas the 
> coefficients mu will have two values mu(1), mu(2), one for each estimation.
> 
> Is this possible to do in R?
> 
> What would be the corresponding syntax in, say, lm?

Your specification is not complete: you haven't said what the errors will be, 
or how x(1,1) and x(2,1) are determined.  I assume you mean independent normal 
errors, but are you willing to assume the variance is the same in both series?  
If so, then your model is almost equivalent to a linear model with concatenated 
x(1,t) and x(2,t) values.  (This would be the "partial likelihood" version of 
the model, where you don't try to fit x(i, 1), but you fit the rest of the 
values conditional on earlier
ones.)

If you want the full likelihood or you want separate variances for the two 
series, you probably need to write out the likelihood explicitly and maximize 
it.

Duncan Murdoch

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