Hi,
I thought you were looking for table(), but the other answers gave you
something really different; I might have wrongly understood your question.
HTH,
Ivan
Le 8/20/2010 12:32, Alain Guillet a écrit :
> Hi,
>
> You can try sapply(levels(as.factor(dat1)),nchar)
>
> Alain
>
> On 20-Aug-10 12:01, Ron Michael wrote:
>> Dear all, let suppose I have following vector:
>>
>>> dat1<- c(rep("asd", 5), rep("xyz", 12), rep("erd", 17))
>>> dat1<- dat1[sample(1:length(dat1), length(dat1), replace=F)]
>>> dat1
>> [1] "erd" "xyz" "erd" "asd" "asd" "erd" "xyz" "asd" "erd" "erd"
>> "asd" "xyz" "erd" "asd" "xyz" "xyz" "erd" "xyz" "erd"
>> [20] "erd" "erd" "xyz" "xyz" "erd" "erd" "erd" "erd" "xyz" "xyz"
>> "xyz" "erd" "xyz" "erd" "erd"
>>
>> Here I want to know the length of replications for each unique
>> items viz "asd", "xyz", and "erd". Is there any R function available
>> to directly implement that?
>> Thanks,
>>
>>
>> [[alternative HTML version deleted]]
>>
>>
>>
>> ______________________________________________
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>> PLEASE do read the posting guide
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>> and provide commented, minimal, self-contained, reproducible code.
>
--
Ivan CALANDRA
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