Hi,
You can try sapply(levels(as.factor(dat1)),nchar)
Alain
On 20-Aug-10 12:01, Ron Michael wrote:
Dear all, let suppose I have following vector:
dat1<- c(rep("asd", 5), rep("xyz", 12), rep("erd", 17))
dat1<- dat1[sample(1:length(dat1), length(dat1), replace=F)]
dat1
[1] "erd" "xyz" "erd" "asd" "asd" "erd" "xyz" "asd" "erd" "erd" "asd" "xyz" "erd" "asd" "xyz" "xyz"
"erd" "xyz" "erd"
[20] "erd" "erd" "xyz" "xyz" "erd" "erd" "erd" "erd" "xyz" "xyz" "xyz" "erd" "xyz" "erd"
"erd"
Here I want to know the length of replications for each unique items viz "asd", "xyz", and "erd". Is there any R function available to directly implement that?
Thanks,
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Alain Guillet
Statistician and Computer Scientist
SMCS - IMMAQ - Université catholique de Louvain
Bureau c.316
Voie du Roman Pays, 20
B-1348 Louvain-la-Neuve
Belgium
tel: +32 10 47 30 50
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
