Thank you for your replies, this actually has little to do with the regular R
code but more to signal what in my package QCA is referred to as a necessity
relation A <- B (A is necessary for B) and sufficiency A -> B (A is sufficient
for B).
If switched by the parser, A -> B becomes B <- A which makes B necessary for A,
while the intention is to signal sufficiency for B.
Capturing in a quoted string is trivial, but I am now experimenting with
substitute() to allow unquoted expressions.
This is especially useful when selecting A and B from the columns of a data
frame, using: c(A, B) instead of c("A", "B") with a lot more quotes for more
complex expressions using more columns.
I would be grateful for any pointer to a project that processes the code while
it is still raw text. I could maybe learn from their code and adapt to my use
case.
Best wishes,
Adrian
> On 13 Apr 2020, at 11:23, Gabriel Becker <gabembec...@gmail.com> wrote:
>
> Adrian,
>
> Indeed, this has come up in a few places, but as Gabor says, there is no such
> thing as right hand assignment at any point after parsing is complete.
>
> This means the only feasible way to detect it, which a few projects do I
> believe, is process the code while it is still raw text, before it goes into
> the parser, and have clever enough regular expressions.
>
> The next question, then, is why are you trying to detect right assignment.
> Doing so can be arguably useful fo linting, its true. Otherwise, though,
> because its not really a "real thing" when the R code is being executed, its
> not something thats generally meaningful to detect in most cases.
>
> Best,
> ~G
>
> On Mon, Apr 13, 2020 at 12:52 AM Gábor Csárdi <csardi.ga...@gmail.com> wrote:
> That parser already flips -> to <- before creating the parse tree.
>
> Gabor
>
> On Mon, Apr 13, 2020 at 8:39 AM Adrian Dușa <dusa.adr...@gmail.com> wrote:
> >
> > I searched and tried for hours, to no avail although it looks simple.
> >
> > (function(x) substitute(x))(A <- B)
> > #A <- B
> >
> > (function(x) substitute(x))(A -> B)
> > # B <- A
> >
> > In the first example, A occurs on the LHS, but in the second example A is
> > somehow evaluated as if it occured on the RHS, despite my understanding
> > that substitute() returns the unevaluated parse tree.
> >
> > Is there any way, or is it even possible to detect the right hand
> > assignment, to determine whether A occurs on the LHS?
> >
> > Thanks in advance for any hint,
> > Adrian
> >
> > —
> > Adrian Dusa
> > University of Bucharest
> > Romanian Social Data Archive
> > Soseaua Panduri nr. 90-92
> > 050663 Bucharest sector 5
> > Romania
> > https://adriandusa.eu
> >
> > ______________________________________________
> > R-devel@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-devel
>
> ______________________________________________
> R-devel@r-project.org mailing list
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—
Adrian Dusa
University of Bucharest
Romanian Social Data Archive
Soseaua Panduri nr. 90-92
050663 Bucharest sector 5
Romania
https://adriandusa.eu
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