That parser already flips -> to <- before creating the parse tree. Gabor
On Mon, Apr 13, 2020 at 8:39 AM Adrian Dușa <dusa.adr...@gmail.com> wrote: > > I searched and tried for hours, to no avail although it looks simple. > > (function(x) substitute(x))(A <- B) > #A <- B > > (function(x) substitute(x))(A -> B) > # B <- A > > In the first example, A occurs on the LHS, but in the second example A is > somehow evaluated as if it occured on the RHS, despite my understanding that > substitute() returns the unevaluated parse tree. > > Is there any way, or is it even possible to detect the right hand assignment, > to determine whether A occurs on the LHS? > > Thanks in advance for any hint, > Adrian > > — > Adrian Dusa > University of Bucharest > Romanian Social Data Archive > Soseaua Panduri nr. 90-92 > 050663 Bucharest sector 5 > Romania > https://adriandusa.eu > > ______________________________________________ > R-devel@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-devel ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel
