'NaN' means "Not a number". according to Python semantics, if you try
to compare it with any other float numbers, it should return FALSE.
just like
>>>
>>>1.0 > 'abc'
False
>>>
Since it always return FALSE, it is not a surprise for your question.
If you wish to get infinitive number, you'd use 'inf' or '-inf', from
IEEE 754 semantics:
>>>a=float(6)
>>>b=float('inf')
>>>c=float('-inf')
Albert Hopkins wrote:
> This issue may have been referred to in
> news:<[EMAIL PROTECTED]> but I didn't
> entirely understand the explanation. Basically I have this:
>
> >>> a = float(6)
> >>> b = float('nan')
> >>> min(a, b)
> 6.0
> >>> min(b, a)
> nan
> >>> max(a, b)
> 6.0
> >>> max(b, a)
> nan
>
> Before I did not know what to expect, but I certainly didn't expect
> this. So my question is what is the min/max of a number and NaN or is it
> not defined (for which I would have expected either an exception to be
> raised or NaN returned in each case).
>
> As a corrollary would I be able to rely on the above behavior or is it
> subject to change (to fix a bug in min/max perhaps :-)?
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