This issue may have been referred to in
news:<[EMAIL PROTECTED]> but I didn't
entirely understand the explanation. Basically I have this:
>>> a = float(6)
>>> b = float('nan')
>>> min(a, b)
6.0
>>> min(b, a)
nan
>>> max(a, b)
6.0
>>> max(b, a)
nan
Before I did not know what to expect, but I certainly didn't expect
this. So my question is what is the min/max of a number and NaN or is it
not defined (for which I would have expected either an exception to be
raised or NaN returned in each case).
As a corrollary would I be able to rely on the above behavior or is it
subject to change (to fix a bug in min/max perhaps :-)?
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