Steve Holden schrieb:
> Precisely. But your example had only one group "(b)" in it, which is
> retrieved using m.group(1). So the subgroups are numbered starting from
> 1 and subgroup 0 is a special case which returns the whole match.
> 
> I know what the Zen says about special cases, but in this case the rules
> were apparently broken with impunity.

Well, the proposal was to interpret m[i] as m.group(i), for all values
of i. I can't see anything confusing with that.

Regards,
Martin
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