Fredrik Lundh schrieb:
>> Ah, right; I misread his proposal as saying that m[:] should return
>> [m[0]] + list(m.groups()) (rather, I expected that m.groups() would
>> include m.group(0)).
>
> match groups are numbered 1..N, not 0..(N-1), in both the API and in the
> RE syntax (and we don't have much control over the latter).
py> m = re.match("a(b)","ab")
py> m.group(0)
'ab'
py> m.group(1)
'b'
>> To answer your first question: it is clearly groups that you want
>> to index, just as the .group() method indexes groups.
>
> so what should len(m) do?
That's a question: should len be supported at all? If so, it's clear
that len(m) == len(m[:]).
Regards,
Martin
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