Re: [PHP] Passing an undetermined amount of arguments by reference

[Jay Moore]

Shawn McKenzie wrote:

Jay Moore wrote:

Jim Lucas wrote:

Jay Moore wrote:

Greetings list.

Say I have a function that escapes a string before being passed to MySQL
like so:

function escape($id, &$string)
{
    $string }

Use an array as an alternate method of sending/returning data to the
second argument.

function escape($id, &$data) {
    if ( is_array($data) ) {
        foreach ( $data AS $k => $v ) {
            escape($id, $v);
            $data[$k] = $v;
        }
    } else {
        $data = mysql_real_escape_string($data, $id);
    }
}

This would handle any number of nested arrays/datasets.

Hope it helps.

Will that work properly?

$a = "'hello'";
$b = "sup";
$c = "\\hola'";

$d = array($a, $b, $c);

escape($id, $d);

Jay

I would try: $d = compact('a', 'b', 'c');

What is the difference?  Please excuse my naivety. :)

Jay

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