[PHP] Passing an undetermined amount of arguments by reference

[Jay Moore]

Greetings list.

Say I have a function that escapes a string before being passed to MySQL 
like so:

function escape($id, &$string)
{
        $string = mysql_real_escape_string($string, $id);
}

I'm passing $string as a reference so I don't have to reassign it like so:

$foo = escape($id, $foo);

Simply calling

escape($id, $foo);

works just fine.


How can I do this if I have a variable number of arguments?  I know I 
can use func_get_args(), func_num_args() and so forth to get the 
arguments but can I still pass by reference?

It'd be so much easier to do

escape($id, $a, $b, $c, $d);

Than

$a = escape($id, a);

and so forth.

Does this make sense?  Is it possible to do?

Thanks in advance,
Jay

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