I have a display_image.php page
<?php
$image = imagecreatefromjpeg($img_url);
if ($image === false) { exit; }
// Get original width and height
echo $width = imagesx($image);
echo $height = imagesy($image);
// New width and height
$new_width = 200;
$new_height = 150;
// Resample
$image_resized = imagecreatetruecolor($new_width, $new_height);
imagecopyresampled($image_resized, $image, 0, 0, 0, 0, $new_width,
$new_height, $width, $height);
// Display resized image
;
header('Content-type: image/jpeg');
imagejpeg($image_resized);
exit();
?>
I want to output this as an image but cannot get it working. I need to pass
the image url something like this I thought would work
echo "<img src=\"display_image.php?img_url=$image_url>";
any ideas?
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