2007. 06. 15, péntek keltezéssel 14.45-kor Ross ezt írta:
> I have a display_image.php page
>
> <?php
>
>
>
> $image = imagecreatefromjpeg($img_url);
where do you get $img_url from? GET request?
then do something like
$img_url = $_GET['img_url'];
if (!file_exists($img_url)) die "bad hacker";
before the above line. this will let you get rid of register_globals,
and does a basic check of input, which is always very important
> if ($image === false) { exit; }
>
> // Get original width and height
> echo $width = imagesx($image);
> echo $height = imagesy($image);
>
> // New width and height
> $new_width = 200;
> $new_height = 150;
>
> // Resample
> $image_resized = imagecreatetruecolor($new_width, $new_height);
> imagecopyresampled($image_resized, $image, 0, 0, 0, 0, $new_width,
> $new_height, $width, $height);
>
> // Display resized image
> ;
> header('Content-type: image/jpeg');
> imagejpeg($image_resized);
> exit();
>
> ?>
>
>
> I want to output this as an image but cannot get it working. I need to pass
> the image url something like this I thought would work
>
> echo "<img src=\"display_image.php?img_url=$image_url>";
this should work. what do you mean by not working? do you get any error
message? anything? without information no one can tell you what's
wrong...
greets
Zoltán Németh
>
>
> any ideas?
>
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