Thanks Curt.
This solution works indeed. BUT, there's one but. Isn't there a way to not
have to tell PHP that I want the return of $this->AddFoo() as a reference?
In the actual code I want to worry as little as possible about specific
things like this. Isn't it a little strange that you have to both let php
know it's returning a reference as well as let it know that it's expecting a
reference as return value?
well you do need to worry about it somewhere, and i would think that the function
declaration:
function &AddFoo()
Would take care of this, but I think there is some strange things going on with the
class. IIRC, issuing a
$foo = $bar->AddFoo();
Doesn't return a reference.
Hopefully someone here can mabey give some more insite as to why there has to be both the declaration and the call references.
function &AddFoo() -and- $foo = &$bar->AddFoo();
Curt.
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