* Thus wrote Wouter van Vliet ([EMAIL PROTECTED]):
> Hi Folks,
>
> I've been using the "passing arguments by reference" thingie for a while
> now. But what I want to do know is something I'm used to using in perl,
> returning a reference.
>
> Situation is as follows.
>
> 19
> 20 function AddFoo() {
Need to let php know this is returning a reference:
function &AddFoo() {
> 21 $Ref = &$this->Foos[];
> 22 $Ref = new Foo();
> 23 return $Ref;
I'm surprized this even works, its kind of confusing, i'd rather do
something like:
$foo = new Foo();
$this->Foos[] = &$foo;
return $foo;
> 26
> 27 $Bar = new Bar();
> 28 $Foo = $Bar->AddFoo();
And then let php know you want this as a reference:
$Foo = &Bar->AddFoo();
Curt
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