El dt 03 de 07 del 2007 a les 08:35 +0200, en/na Sebastian Haase va escriure: > any comments !? > > On 6/25/07, Sebastian Haase <[EMAIL PROTECTED]> wrote: > > Hi, > > Suppose I'm on a little-edian system. > > Could I have a little-endian numpy array arr, where > > arr.dtype.byteorder > > would actually be "<" > > instead of "=" !?
You can always use arr.dtype.str[0], which I think it always returns a '<', '>' or '|': In [2]:a=numpy.array([1]) In [3]:a.dtype.byteorder Out[3]:'=' In [4]:a.dtype.str Out[4]:'<i4' In [5]:a.dtype.str[0] Out[5]:'<' > > There are two kinds of systems: little edian and big endian. > > But there are three possible byteorder values: "<", ">" and "=" > > > > I assume that if arr.dtype.byteorder is "=" > > then, even on a little endian system > > the comparison arr.dtype.byteorder == "<" still fails !? > > Or are the == and != operators overloaded !? No, this will fail. The == and != are not overloaded because dtype.byteorder is a pure python string: In [11]:type(a.dtype.byteorder) Out[11]:<type 'str'> Cheers, -- Francesc Altet | Be careful about using the following code -- Carabos Coop. V. | I've only proven that it works, www.carabos.com | I haven't tested it. -- Donald Knuth _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
