Hi, Suppose I'm on a little-edian system. Could I have a little-endian numpy array arr, where arr.dtype.byteorder would actually be "<" instead of "=" !?
There are two kinds of systems: little edian and big endian. But there are three possible byteorder values: "<", ">" and "=" I assume that if arr.dtype.byteorder is "=" then, even on a little endian system the comparison arr.dtype.byteorder == "<" still fails !? Or are the == and != operators overloaded !? Thanks, Sebastian Haase _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
