On Tue, 27 Mar 2007, Zachary Pincus wrote: > M[i], which equals M[i,:]
Of course this equality must break. That was stated at the outset. As I said before, this may be impossible or undesirable. But, as I said before, it seems prima facie natural for M[i] to be ordinary Python indexing while M[i,:] is numpy indexing, each with its own natural interpretation. In any case, you may be spending too much energy on this. I am not a developer, and no developer has expressed a desire to make such a change. The current behavior is currently safe (if odd). Cheers, Alan Isaac _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
