On 2018年01月26日 10:44, Michael S. Tsirkin wrote:
On Fri, Jan 26, 2018 at 10:37:58AM +0800, Jason Wang wrote:
On 2018年01月26日 07:36, Michael S. Tsirkin wrote:
Lockless __ptr_ring_empty requires that consumer head is read and
written at once, atomically. Annotate accordingly to make sure compiler
does it correctly. Switch locked callers to __ptr_ring_peek which does
not support the lockless operation.
Signed-off-by: Michael S. Tsirkin <m...@redhat.com>
---
include/linux/ptr_ring.h | 11 ++++++++---
1 file changed, 8 insertions(+), 3 deletions(-)
diff --git a/include/linux/ptr_ring.h b/include/linux/ptr_ring.h
index 8594c7b..9a72d8f 100644
--- a/include/linux/ptr_ring.h
+++ b/include/linux/ptr_ring.h
@@ -196,7 +196,9 @@ static inline void *__ptr_ring_peek(struct ptr_ring *r)
*/
static inline bool __ptr_ring_empty(struct ptr_ring *r)
{
- return !__ptr_ring_peek(r);
+ if (likely(r->size))
+ return !r->queue[READ_ONCE(r->consumer_head)];
+ return true;
}
So after patch 8, __ptr_ring_peek() did:
static inline void *__ptr_ring_peek(struct ptr_ring *r)
{
if (likely(r->size))
return READ_ONCE(r->queue[r->consumer_head]);
return NULL;
}
Looks like a duplication.
Thanks
Nope - they are different.
The reason is that __ptr_ring_peek does not need to read the consumer_head once
since callers have a lock,
I get this.
and __ptr_ring_empty does not need to read
the queue once since it merely compares it to 0.
Do this still work if it was called inside a loop?
Thanks