hawkinsw added inline comments.
================
Comment at: lldb/tools/intel-features/intel-mpx/cli-wrapper-mpxtable.cpp:66
- if ((lbound == one_cmpl64 || one_cmpl32) && ubound == 0) {
result.Printf("Null bounds on map: pointer value = 0x%" PRIu64 "\n",
value);
----------------
According to https://en.cppreference.com/w/cpp/language/operator_precedence, I
would read the left operand of the `&&` as
1. The `==` has higher precedence than `||` so, `b = (lbound == one_compl64)`
2. `b || one_cmpl32`
which does not seem like what the original author intended. I absolutely think
that the fix is correct, but I just wanted to get everyone's feedback on
whether this seems like more than just a "suspicious bitwise expression" (and
more like a "mistaken bitwise expression").
All that said, I could be completely, 100% wrong. And, if I am, feel free to
ignore me!
Repository:
rG LLVM Github Monorepo
CHANGES SINCE LAST ACTION
https://reviews.llvm.org/D131312/new/
https://reviews.llvm.org/D131312
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