Hi,
Thanks for your quick response.
On 9 October 2012 13:39, <d...@gnu.org> wrote:
> Viresh Kumar wrote:
>> When we have following declaration:
>>
>> struct foo {
>> char array[5];
>> ....
>> };
>>
>> And have a definition like:
>>
>> struct foo foo_abc = {
>> .array = "12345",
>> };
>>
>> Problem here is: size of array is 5 bytes and so we can actually add a
>> string with four characters only to it, as '\0' will take
>> an additional space.
>>
>> But with my definition of foo_abc.. i had 5 characters + '\0'... that
>> will make it 6 and that will overflow the array..
>>
>> What will actually happen here?
>> - compiler will not add '\0' at all?
>> - or it will go outside of boundaries of array?
>
> I think it will go outside of boundaries. You should avoid adding the \0 or
> redefine char array to hold up to 6 chars.
Ok. So it will overwrite whatever follows the memory of this struct if
array is the
last element in this struct.
> struct foo {
> ....
> char array[5];
> };
I am not adding '\0' in my string at all. Is this '\0' always added by compiler,
even in above situation?
--
viresh
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