Viresh Kumar wrote:
> When we have following declaration:
>
> struct foo {
> char array[5];
> ....
> };
>
> And have a definition like:
>
> struct foo foo_abc = {
> .array = "12345",
> };
>
> Problem here is: size of array is 5 bytes and so we can actually add a
> string with four characters only to it, as '\0' will take
> an additional space.
>
> But with my definition of foo_abc.. i had 5 characters + '\0'... that
> will make it 6 and that will overflow the array..
>
> What will actually happen here?
> - compiler will not add '\0' at all?
> - or it will go outside of boundaries of array?
I think it will go outside of boundaries. You should avoid adding the \0 or
redefine char array to hold up to 6 chars.
Regards
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