frankliee commented on issue #2222: URL: https://github.com/apache/iceberg-python/issues/2222#issuecomment-3095500764
> > there is not api to get the snapshot_id from a given tag > > as @.jayceslesar mentioned, `Table` has `snapshot_by_name` which can take in a tag name. > > Something like this should work, > > ``` > snapshot = tbl.snapshot_by_name(tag_name) > scan(xxx, snapshot_id = snapshot.snapshot_id, xxx) > ``` > > I dont think we need a new scan api, we can just reuse the original I works -- This is an automated message from the Apache Git Service. To respond to the message, please log on to GitHub and use the URL above to go to the specific comment. To unsubscribe, e-mail: issues-unsubscr...@iceberg.apache.org For queries about this service, please contact Infrastructure at: us...@infra.apache.org --------------------------------------------------------------------- To unsubscribe, e-mail: issues-unsubscr...@iceberg.apache.org For additional commands, e-mail: issues-h...@iceberg.apache.org