On Mon, Mar 22, 2021 at 10:55 AM Alex john <blackbriar...@gmail.com> wrote:
> Transform {
> id: trefoilMeshTransform
> translation:Qt.vector3d(Qt.vector2D(100, 100)).unproject(
> modelView ,mainCam.projectionMatrix, forwardRenderer.viewportRect)
> property real theta: 0.0
> property real phi:0.0
> property real roll: 0.0
> rotation: fromEulerAngles(theta, phi, roll)
> scale: root.scale
> }
I used the following function to get the 3d coordinates using the 2d,
by refering to the source code
https://code.woboq.org/qt5/qtbase/src/gui/math3d/qvector3d.cpp.html#_ZNK9QVector3D9unprojectERK10QMatrix4x4S2_RK5QRect
I need to render the 3d cube exactly where the Rectangle{x:100, y:100}
renders however there is lot of offset and I think the calculations is
somewhere going wrong. Can clue ?
function projectPointsto3d(){
var ptX = 100
var ptY = 100
var windowPt = Qt.vector4d(ptX,ptY,1,1)
var mat = mainCam.projectionMatrix.times(mainCam.viewMatrix)
var inverse = mat.inverted()
var normalize = Qt.vector4d(1,1,1,1)
windowPt.x = (windowPt.x -
forwardRenderer.viewportRect.x)/forwardRenderer.viewportRect.width
windowPt.y = (windowPt.y -
forwardRenderer.viewportRect.y)/forwardRenderer.viewportRect.height
windowPt = windowPt.times(2).minus(normalize)
var a = inverse.times(windowPt)
var division = a.w (if i use (1/a.w) teh 3d values will be
very high and I do not see object)
a = a.times(division)
return a.toVector3d()
}
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