Re: no encrypt key for gfp@posteo.at

[gfp]

Hi,
after setting up .gnupg/gpg.conf
with:

default-recipient g...@posteo.at 2453E9849BB91599B128FFE7AC95367953582A3C
hidden-encrypt-to g...@posteo.at 2453E9849BB91599B128FFE7AC95367953582A3C

I tried to encrypt a mail in gnus.

and it gave me the backtrace:


  mml-generate-mime(nil nil)
  message-encode-message-body()
  message-send-mail(nil)
  message-send-via-mail(nil)
  message-send(nil)
  message-send-and-exit(nil)
  funcall-interactively(message-send-and-exit nil)
  command-execute(message-send-and-exit)


Earlier it was possible to encrypt a mail in gnus.

I guess I have to add something in my gpg.conf file

thanks

Gottfried


Am 17.03.26 um 13:03 schrieb gfp:

Debugger entered--Lisp error: (epg-error "Encrypt failed" "Unusable public key: g...@posteo.at 2453E9849BB91599B128FFE7AC95367953582A3C; Exit") signal(epg-error ("Encrypt failed" "Unusable public key: g...@posteo.at 2453E9849BB91599B128FFE7AC95367953582A3C; Exit")) mml-secure-epg-encrypt(OpenPGP (part (encrypt . "pgpmime") (tag-location . 249) (contents . "\ntest\n")) nil) mml2015-epg-encrypt((part (encrypt . "pgpmime") (tag-location . 249) (contents . "\ntest\n")) nil) mml2015-encrypt((part (encrypt . "pgpmime") (tag-location . 249) (contents . "\ntest\n")) nil) mml-pgpmime-encrypt-buffer((part (encrypt . "pgpmime") (tag-location . 249) (contents . "\ntest\n"))) mml-generate-mime-1((part (encrypt . "pgpmime") (tag-location . 249) (contents . "\ntest\n")))

Additional information:

in Emacs, opening the pgp option
in /tools/Encryption Decryption/...

it gives me the key:

   u AC95367953582A3C gfp (2026) <g...@posteo.at>

but there is also no "0x" in front of a key.

Gottfried


Am 17.03.26 um 11:58 schrieb gfp:

Am 17.03.26 um 10:51 schrieb Adam Sjøgren:

gfp writes:

I don´t know who is Bob?

It's an English idiom, which roughly means "and your problem is
solved": https://en.wikipedia.org/wiki/Bob%27s_your_uncle

I found in "man gpg" those two options:
"default-recipient" and
"hidden-encrypt-to"

Super!
Did you find out what value to set them to?

no

You set the to the id if your key - so if you run:

   gpg --list-keys g...@posteo.at

the id is the string that starts "0x" in the first line - perhaps it
shows 0xAC95367953582A3C ?

if I run:

  gpg --list-keys g...@posteo.at

it gives me:

no id with the start of "0x"

but:

pub   ed25519 2026-03-03 [SC]
       2453E9849BB......  long number
uid        [ ultimativ ] gfp (2026) <g...@posteo.at>
sub   cv25519 2026-03-03 [E]

So how can I find the ID?

You set those two parameters in the configuration file for gpg,
which is ~/.gnupg/gpg.conf

I don´t have a gpg.conf file in my  ~/.gnupg/

Then you create it, and put in lines with the two options and the
0x... value after each.


   Best regards,

     Adam

thanks

Gottfried

--
Mit freundlichen Grüßen

G. Preihs

OpenPGP_0xAC95367953582A3C.asc
Description: OpenPGP public key

OpenPGP_signature.asc
Description: OpenPGP digital signature