Re: no encrypt key for gfp@posteo.at

[gfp]

Additional information:

in Emacs, opening the pgp option
in /tools/Encryption Decryption/...

it gives me the key:

  u AC95367953582A3C gfp (2026) <g...@posteo.at>

but there is also no "0x" in front of a key.

Gottfried


Am 17.03.26 um 11:58 schrieb gfp:

Am 17.03.26 um 10:51 schrieb Adam Sjøgren:

gfp writes:

I don´t know who is Bob?

It's an English idiom, which roughly means "and your problem is
solved": https://en.wikipedia.org/wiki/Bob%27s_your_uncle

I found in "man gpg" those two options:
"default-recipient" and
"hidden-encrypt-to"

Super!
Did you find out what value to set them to?

no

You set the to the id if your key - so if you run:

   gpg --list-keys g...@posteo.at

the id is the string that starts "0x" in the first line - perhaps it
shows 0xAC95367953582A3C ?

if I run:

  gpg --list-keys g...@posteo.at

it gives me:

no id with the start of "0x"

but:

pub   ed25519 2026-03-03 [SC]
       2453E9849BB......  long number
uid        [ ultimativ ] gfp (2026) <g...@posteo.at>
sub   cv25519 2026-03-03 [E]

So how can I find the ID?

You set those two parameters in the configuration file for gpg,
which is ~/.gnupg/gpg.conf

I don´t have a gpg.conf file in my  ~/.gnupg/

Then you create it, and put in lines with the two options and the
0x... value after each.


   Best regards,

     Adam

thanks

Gottfried

OpenPGP_0xAC95367953582A3C.asc
Description: OpenPGP public key

OpenPGP_signature.asc
Description: OpenPGP digital signature