Bradley Lucier wrote:
> If -ffinite-math-only is specified, then producing NaN instead of inf
> should be allowed.
Agreed. After all, -finite-math says:
Allow optimizations for floating-point arithmetic that assume that
arguments and results are not NaNs or +-Infs.
Since the compiler can assume the output isn't a NaN or an Inf, it can
freely switch one and the other.
> If -fno-finite-math-only is specified, then the generated code should
> "do the right thing" if an argument or result is inf or NaN.
Also agreed.
--
Mark Mitchell
CodeSourcery
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