On 19 August 2014 06:58, Marek Polacek <pola...@redhat.com> wrote: > On Mon, Aug 18, 2014 at 10:57:58PM +0200, Manuel López-Ibáñez wrote: >> On 18 August 2014 22:04, Marek Polacek <pola...@redhat.com> wrote: >> > +void >> > +maybe_warn_bool_compare (location_t loc, enum tree_code code, tree op0, >> > + tree op1) >> > +{ >> > + if (TREE_CODE_CLASS (code) != tcc_comparison) >> > + return; >> > + >> > + /* <boolean> CMP <cst> */ >> > + if (TREE_CODE (op1) == INTEGER_CST >> > + && !integer_zerop (op1) >> > + && !integer_onep (op1)) >> > + { >> > + if (code == EQ_EXPR >> > + || ((code == GT_EXPR || code == GE_EXPR) >> > + && tree_int_cst_sgn (op1) == 1) >> > + || ((code == LT_EXPR || code == LE_EXPR) >> > + && tree_int_cst_sgn (op1) == -1)) >> > + warning_at (loc, OPT_Wbool_compare, "comparison of constant %qE " >> > + "with boolean expression is always false", op1); >> > + else >> > + warning_at (loc, OPT_Wbool_compare, "comparison of constant %qE " >> > + "with boolean expression is always true", op1); >> > + } >> > + /* <cst> CMP <boolean> */ >> > + else if (TREE_CODE (op0) == INTEGER_CST >> > + && !integer_zerop (op0) >> > + && !integer_onep (op0)) >> > + { >> > + if (code == EQ_EXPR >> > + || ((code == GT_EXPR || code == GE_EXPR) >> > + && tree_int_cst_sgn (op0) == -1) >> > + || ((code == LT_EXPR || code == LE_EXPR) >> > + && tree_int_cst_sgn (op0) == 1)) >> > + warning_at (loc, OPT_Wbool_compare, "comparison of constant %qE " >> > + "with boolean expression is always false", op0); >> > + else >> > + warning_at (loc, OPT_Wbool_compare, "comparison of constant %qE " >> > + "with boolean expression is always true", op0); >> > + } >> >> Perhaps you can save some repetition by doing first: >> >> tree op = (TREE_CODE (op1) == INTEGER_CST) ? op1 : op0; >> if (TREE_CODE (op) == INTEGER_CST >> && !integer_zerop (op) > > Not sure about that: it matters whether the CST is a LHS or a RHS > - because we want to say if the comparison is always true or false. > I tried to introduce some bool flag, but that didn't really help > readability IMHO. (The tree_int_cst_sgn is compared to 1 and -1, or > to -1 and 1.)
Oh, yes. I missed that. Sorry. What about? tree op = (TREE_CODE (op0) == INTEGER_CST) ? op0 : (TREE_CODE (op1) == INTEGER_CST) ? op1 : NULL_TREE; if (op == NULL_TREE) return; if (!integer_zerop (op) && !integer_onep(op)) { int sign = (TREE_CODE (op0) == INTEGER_CST) ? tree_int_cst_sgn (op) : -tree_int_cst_sgn (op); if (code == EQ_EXPR || ((code == GT_EXPR || code == GE_EXPR) && sign < 0) || ((code == LT_EXPR || code == LE_EXPR) && sign > 0)) or some variation of the above could work, no? Cheers, Manuel.