On 6/13/19 9:34 AM, Jakub Jelinek wrote:
On Thu, Jun 13, 2019 at 09:30:37AM -0600, Martin Sebor wrote:
The size of the access above doesn't look right. The test is:
It is correct. You have MEM <int[5]> [(int *)&i], which is
the same thing as i itself, and on this you apply an ARRAY_REF,
which is printed after it, with index j_1(D). ARRAY_REF is applied on
arrays and the result type is the array element type, so int in this case.
Aah, it's two REFs in one. I misread the array index as being
a part of the MEM_REF operand, like this:
MEM <int[5]> [((int *)&i)[j_1(D)]] = 1;
I guess I've never noticed this before. Why is the whole thing
not simplified to an ARRAY_REF?
i[j_2(D)] = 1;
Martin
