Hi! If there are lambdas in C++11 constexpr return-stmts, we get implicit typedefs of the lambda types, but those are artificial and we should ignore them.
Bootstrapped/regtested on x86_64-linux and i686-linux, ok for trunk? 2015-02-16 Paolo Carlini <paolo.carl...@oracle.com> Jakub Jelinek <ja...@redhat.com> PR c++/65075 * constexpr.c (check_constexpr_bind_expr_vars): Allow implicit typedefs for lambda types. * g++.dg/cpp0x/pr65075.C: New test. --- gcc/cp/constexpr.c.jj 2015-02-14 00:19:49.000000000 +0100 +++ gcc/cp/constexpr.c 2015-02-16 15:12:06.260262857 +0100 @@ -416,7 +416,8 @@ check_constexpr_bind_expr_vars (tree t) for (tree var = BIND_EXPR_VARS (t); var; var = DECL_CHAIN (var)) if (TREE_CODE (var) == TYPE_DECL - && DECL_IMPLICIT_TYPEDEF_P (var)) + && DECL_IMPLICIT_TYPEDEF_P (var) + && !LAMBDA_TYPE_P (TREE_TYPE (var))) return false; return true; } --- gcc/testsuite/g++.dg/cpp0x/pr65075.C.jj 2015-02-16 15:09:48.405517062 +0100 +++ gcc/testsuite/g++.dg/cpp0x/pr65075.C 2015-02-16 15:09:23.000000000 +0100 @@ -0,0 +1,17 @@ +// PR c++/65075 +// { dg-do compile { target c++11 } } + +typedef void (*E) (); +template <class T> +constexpr E +bar (bool a) +{ + return a ? []() {} : []() {}; +} + +void +foo () +{ + (bar<int> (false)) (); + (bar<int> (true)) (); +} Jakub