https://gcc.gnu.org/bugzilla/show_bug.cgi?id=98920
Florian Weimer <fw at gcc dot gnu.org> changed:
What |Removed |Added
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CC| |fw at gcc dot gnu.org
--- Comment #7 from Florian Weimer <fw at gcc dot gnu.org> ---
I think libsanitizer falls back to a version-less lookup if the version cannot
be found. Therefore, if the glibc baseline is after 2.3.4, the version-less
lookup will find the unversioned symbol, which has the right behavior.
I don't see any architecture that has two regexec symbols, but does not use
GLIBC_2.3.4 for the most recent symbol, based on this command in the glibc
source tree:
git grep -c ' regexec F' | grep :2$ | cut -d: -f1 | xargs grep ' regexec F'
A comment in the interceptor might make sense, though.
