http://gcc.gnu.org/bugzilla/show_bug.cgi?id=55885
--- Comment #2 from kwieder at polytechnic dot edu.na 2013-01-06 12:14:16 UTC
---
Thanks for the quick response.
Why is
INT_MIN % -1
ok
and why is
int b = -1;
INT_MIN % b
not ok.
I"m well aware of INT_MIN / -1 is overflowing. If your are using a division
for the % operator, which you probably do, then INT_MIN % -1 should also crash.
Regards,
Klaus
On Jan 6, 2013, at 1:01 PM, [email protected] wrote:
> if they have minimal value
>
> Date: Sun, 06 Jan 2013 11:01:33 +0000
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> http://gcc.gnu.org/bugzilla/show_bug.cgi?id=55885
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> Andreas Schwab <[email protected]> changed:
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>
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> What |Removed |Added
>
> ----------------------------------------------------------------------------
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> Status|UNCONFIRMED |RESOLVED
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> Resolution| |INVALID
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>
> --- Comment #1 from Andreas Schwab <[email protected]> 2013-01-06
> 11:01:33 UTC ---
>
> INT_MIN % -1 is undefined due to overflow. -fwrapv has no effect on division
>
> operations.
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